How to generate a zip file from given file list (Django)?

import os
import shutil
from io import BytesIO
from zipfile import ZipFile
from django.core.files.storage import FileSystemStorage
from django.http import HttpResponse
from django.conf import settings

local_storage = FileSystemStorage()


class ZipResponseMixin:
    def response(self, request, files: list, folder_name: str) -> HttpResponse:
        """Zip Response
        Generate a zip file from given file list and return Http response (Force download)
        :param request: request Object
        :param files: list of file like objects saved in models
        :param folder_name: desired folder name
        :return:
        """
        folder_abs_path = f"{settings.MEDIA_ROOT}/temp-dl/{str(request.user.first_name)}/{folder_name}"
        if os.path.exists(folder_abs_path):
            shutil.rmtree(folder_abs_path)
        os.makedirs(folder_abs_path)
        file_names = list()
        for file in files:
            self._temp_save(file, file_names, folder_abs_path)
        buffer = BytesIO()
        zf = ZipFile(buffer, "w")
        for name in file_names:
            file_abs_path = folder_abs_path + "/" + name
            zf.write(file_abs_path, name)
        zf.close()
        response = HttpResponse(buffer.getvalue(), content_type="application/zip")
        response["Content-Disposition"] = f"attachment; filename={folder_name}.zip"
        return response

    def _temp_save(self, file, file_names, folder_abs_path):
        if file is not None:
            file_name = os.path.basename(file.name)
            file_abs_path = folder_abs_path + "/" + file_name
            local_storage.save(file_abs_path, file)
            file_names.append(file_name)